6(x^2+2x)=2(3x^2+12)

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Solution for 6(x^2+2x)=2(3x^2+12) equation:


Simplifying
6(x2 + 2x) = 2(3x2 + 12)

Reorder the terms:
6(2x + x2) = 2(3x2 + 12)
(2x * 6 + x2 * 6) = 2(3x2 + 12)
(12x + 6x2) = 2(3x2 + 12)

Reorder the terms:
12x + 6x2 = 2(12 + 3x2)
12x + 6x2 = (12 * 2 + 3x2 * 2)
12x + 6x2 = (24 + 6x2)

Add '-6x2' to each side of the equation.
12x + 6x2 + -6x2 = 24 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
12x + 0 = 24 + 6x2 + -6x2
12x = 24 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
12x = 24 + 0
12x = 24

Solving
12x = 24

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '12'.
x = 2

Simplifying
x = 2

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